Integrand size = 20, antiderivative size = 69 \[ \int \frac {\left (c x^2\right )^{5/2} (a+b x)^n}{x^4} \, dx=-\frac {a c^2 \sqrt {c x^2} (a+b x)^{1+n}}{b^2 (1+n) x}+\frac {c^2 \sqrt {c x^2} (a+b x)^{2+n}}{b^2 (2+n) x} \]
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Time = 0.01 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {15, 45} \[ \int \frac {\left (c x^2\right )^{5/2} (a+b x)^n}{x^4} \, dx=\frac {c^2 \sqrt {c x^2} (a+b x)^{n+2}}{b^2 (n+2) x}-\frac {a c^2 \sqrt {c x^2} (a+b x)^{n+1}}{b^2 (n+1) x} \]
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Rule 15
Rule 45
Rubi steps \begin{align*} \text {integral}& = \frac {\left (c^2 \sqrt {c x^2}\right ) \int x (a+b x)^n \, dx}{x} \\ & = \frac {\left (c^2 \sqrt {c x^2}\right ) \int \left (-\frac {a (a+b x)^n}{b}+\frac {(a+b x)^{1+n}}{b}\right ) \, dx}{x} \\ & = -\frac {a c^2 \sqrt {c x^2} (a+b x)^{1+n}}{b^2 (1+n) x}+\frac {c^2 \sqrt {c x^2} (a+b x)^{2+n}}{b^2 (2+n) x} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.67 \[ \int \frac {\left (c x^2\right )^{5/2} (a+b x)^n}{x^4} \, dx=\frac {c^3 x (a+b x)^{1+n} (-a+b (1+n) x)}{b^2 (1+n) (2+n) \sqrt {c x^2}} \]
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Time = 0.27 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.67
method | result | size |
gosper | \(-\frac {\left (c \,x^{2}\right )^{\frac {5}{2}} \left (b x +a \right )^{1+n} \left (-b n x -b x +a \right )}{b^{2} x^{5} \left (n^{2}+3 n +2\right )}\) | \(46\) |
risch | \(-\frac {c^{2} \sqrt {c \,x^{2}}\, \left (-b^{2} n \,x^{2}-a b n x -b^{2} x^{2}+a^{2}\right ) \left (b x +a \right )^{n}}{x \,b^{2} \left (2+n \right ) \left (1+n \right )}\) | \(63\) |
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Time = 0.23 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.10 \[ \int \frac {\left (c x^2\right )^{5/2} (a+b x)^n}{x^4} \, dx=\frac {{\left (a b c^{2} n x - a^{2} c^{2} + {\left (b^{2} c^{2} n + b^{2} c^{2}\right )} x^{2}\right )} \sqrt {c x^{2}} {\left (b x + a\right )}^{n}}{{\left (b^{2} n^{2} + 3 \, b^{2} n + 2 \, b^{2}\right )} x} \]
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\[ \int \frac {\left (c x^2\right )^{5/2} (a+b x)^n}{x^4} \, dx=\begin {cases} \frac {a^{n} \left (c x^{2}\right )^{\frac {5}{2}}}{2 x^{3}} & \text {for}\: b = 0 \\\int \frac {\left (c x^{2}\right )^{\frac {5}{2}}}{x^{4} \left (a + b x\right )^{2}}\, dx & \text {for}\: n = -2 \\\int \frac {\left (c x^{2}\right )^{\frac {5}{2}}}{x^{4} \left (a + b x\right )}\, dx & \text {for}\: n = -1 \\- \frac {a^{2} \left (c x^{2}\right )^{\frac {5}{2}} \left (a + b x\right )^{n}}{b^{2} n^{2} x^{5} + 3 b^{2} n x^{5} + 2 b^{2} x^{5}} + \frac {a b n x \left (c x^{2}\right )^{\frac {5}{2}} \left (a + b x\right )^{n}}{b^{2} n^{2} x^{5} + 3 b^{2} n x^{5} + 2 b^{2} x^{5}} + \frac {b^{2} n x^{2} \left (c x^{2}\right )^{\frac {5}{2}} \left (a + b x\right )^{n}}{b^{2} n^{2} x^{5} + 3 b^{2} n x^{5} + 2 b^{2} x^{5}} + \frac {b^{2} x^{2} \left (c x^{2}\right )^{\frac {5}{2}} \left (a + b x\right )^{n}}{b^{2} n^{2} x^{5} + 3 b^{2} n x^{5} + 2 b^{2} x^{5}} & \text {otherwise} \end {cases} \]
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Time = 0.22 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.74 \[ \int \frac {\left (c x^2\right )^{5/2} (a+b x)^n}{x^4} \, dx=\frac {{\left (b^{2} c^{\frac {5}{2}} {\left (n + 1\right )} x^{2} + a b c^{\frac {5}{2}} n x - a^{2} c^{\frac {5}{2}}\right )} {\left (b x + a\right )}^{n}}{{\left (n^{2} + 3 \, n + 2\right )} b^{2}} \]
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\[ \int \frac {\left (c x^2\right )^{5/2} (a+b x)^n}{x^4} \, dx=\int { \frac {\left (c x^{2}\right )^{\frac {5}{2}} {\left (b x + a\right )}^{n}}{x^{4}} \,d x } \]
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Time = 0.25 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.36 \[ \int \frac {\left (c x^2\right )^{5/2} (a+b x)^n}{x^4} \, dx=\frac {{\left (a+b\,x\right )}^n\,\left (\frac {c^2\,x^2\,\sqrt {c\,x^2}\,\left (n+1\right )}{n^2+3\,n+2}-\frac {a^2\,c^2\,\sqrt {c\,x^2}}{b^2\,\left (n^2+3\,n+2\right )}+\frac {a\,c^2\,n\,x\,\sqrt {c\,x^2}}{b\,\left (n^2+3\,n+2\right )}\right )}{x} \]
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